8y^2=392

Solution for 8y^2=392 equation:

8y^2=392

We move all terms to the left:

8y^2-(392)=0

a = 8; b = 0; c = -392;
Δ = b2-4ac
Δ = 02-4·8·(-392)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*8}=\frac{-112}{16}
=-7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*8}=\frac{112}{16}
=7
$